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// @Title: 反转字符串 (Reverse String)
// @Author: 15816537946@163.com
// @Date: 2019-09-04 16:55:21
// @Runtime: 1592 ms
// @Memory: 31 MB
/*
 * @lc app=leetcode.cn id=344 lang=golang
 *
 * [344] 反转字符串
 *
 * https://leetcode-cn.com/problems/reverse-string/description/
 *
 * algorithms
 * Easy (67.53%)
 * Likes:    165
 * Dislikes: 0
 * Total Accepted:    71.5K
 * Total Submissions: 105.9K
 * Testcase Example:  '["h","e","l","l","o"]'
 *
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
 * 
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 * 
 * 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
 * 
 * 
 * 
 * 示例 1：
 * 
 * 输入：["h","e","l","l","o"]
 * 输出：["o","l","l","e","h"]
 * 
 * 
 * 示例 2：
 * 
 * 输入：["H","a","n","n","a","h"]
 * 输出：["h","a","n","n","a","H"]
 * 
 */
func reverseString(s []byte)  {
	for i,j:=0, len(s)-1;i<j;i,j=i+1,j-1 {
		s[i],s[j] = s[j],s[i]
	}
}