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# 2181. Merge Nodes in Between Zeros

## Description

You are given the `head`

of a linked list, which contains a series of integers **separated** by `0`

's. The **beginning** and **end** of the linked list will have `Node.val == 0`

.

For **every **two consecutive `0`

's, **merge** all the nodes lying in between them into a single node whose value is the **sum** of all the merged nodes. The modified list should not contain any `0`

's.

Return *the* `head`

*of the modified linked list*.

**Example 1:**

Input:head = [0,3,1,0,4,5,2,0]Output:[4,11]Explanation:The above figure represents the given linked list. The modified list contains - The sum of the nodes marked in green: 3 + 1 = 4. - The sum of the nodes marked in red: 4 + 5 + 2 = 11.

**Example 2:**

Input:head = [0,1,0,3,0,2,2,0]Output:[1,3,4]Explanation:The above figure represents the given linked list. The modified list contains - The sum of the nodes marked in green: 1 = 1. - The sum of the nodes marked in red: 3 = 3. - The sum of the nodes marked in yellow: 2 + 2 = 4.

**Constraints:**

- The number of nodes in the list is in the range
`[3, 2 * 10`

.^{5}] `0 <= Node.val <= 1000`

- There are
**no**two consecutive nodes with`Node.val == 0`

. - The
**beginning**and**end**of the linked list have`Node.val == 0`

.