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Given an array
nums of size
n, return the majority element.
The majority element is the element that appears more than
⌊n / 2⌋ times. You may assume that the majority element always exists in the array.
Input: nums = [3,2,3] Output: 3
Input: nums = [2,2,1,1,1,2,2] Output: 2
n == nums.length
1 <= n <= 5 * 104
-109 <= nums[i] <= 109
Follow-up: Could you solve the problem in linear time and in