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剑指 Offer II 005. 单词长度的最大乘积
题目描述
给定一个字符串数组 words
,请计算当两个字符串 words[i]
和 words[j]
不包含相同字符时,它们长度的乘积的最大值。假设字符串中只包含英语的小写字母。如果没有不包含相同字符的一对字符串,返回 0。
示例 1:
输入: words =["abcw","baz","foo","bar","fxyz","abcdef"]
输出:16 解释: 这两个单词为
"abcw", "fxyz"
。它们不包含相同字符,且长度的乘积最大。
示例 2:
输入: words =["a","ab","abc","d","cd","bcd","abcd"]
输出:4 解释:
这两个单词为"ab", "cd"
。
示例 3:
输入: words =["a","aa","aaa","aaaa"]
输出:0 解释: 不存在这样的两个单词。
提示:
2 <= words.length <= 1000
1 <= words[i].length <= 1000
words[i]
仅包含小写字母
注意:本题与主站 318 题相同:https://leetcode-cn.com/problems/maximum-product-of-word-lengths/