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| // @Title: 反转字符串 (Reverse String)
// @Author: 15816537946@163.com
// @Date: 2019-09-04 16:55:21
// @Runtime: 1592 ms
// @Memory: 31 MB
/*
* @lc app=leetcode.cn id=344 lang=golang
*
* [344] 反转字符串
*
* https://leetcode-cn.com/problems/reverse-string/description/
*
* algorithms
* Easy (67.53%)
* Likes: 165
* Dislikes: 0
* Total Accepted: 71.5K
* Total Submissions: 105.9K
* Testcase Example: '["h","e","l","l","o"]'
*
* 编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
*
* 不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
*
* 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
*
*
*
* 示例 1:
*
* 输入:["h","e","l","l","o"]
* 输出:["o","l","l","e","h"]
*
*
* 示例 2:
*
* 输入:["H","a","n","n","a","h"]
* 输出:["h","a","n","n","a","H"]
*
*/
func reverseString(s []byte) {
for i,j:=0, len(s)-1;i<j;i,j=i+1,j-1 {
s[i],s[j] = s[j],s[i]
}
}
|